a^2=36+27.04

Solution for a^2=36+27.04 equation:

a^2=36+27.04

We move all terms to the left:

a^2-(36+27.04)=0

We add all the numbers together, and all the variables

a^2-(63.04)=0

We add all the numbers together, and all the variables

a^2-63.04=0

a = 1; b = 0; c = -63.04;
Δ = b2-4ac
Δ = 02-4·1·(-63.04)
Δ = 252.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{252.16}}{2*1}=\frac{0-\sqrt{252.16}}{2}
=-\frac{\sqrt{}}{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{252.16}}{2*1}=\frac{0+\sqrt{252.16}}{2}
=\frac{\sqrt{}}{2}
$